The self-inductance of a straight conductor i | vedclass

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(A) The self-inductance $L$ of a coil is given by the relation $L = \frac{N \phi}{I}$.For a straight conductor,the number of turns $N$ is effectively

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Zero

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(A) The self-inductance $L$ of a coil is given by the relation $L = \frac{N \phi}{I}$.For a straight conductor,the number of turns $N$ is effectively $0$.Since the self-inductance is directly proportional to the number of turns ($L \propto N^2$ or $L \propto N$ depending on geometry),for a straight wire where there are no loops or turns,the magnetic flux linkage is zero.Therefore,the self-inductance of a straight conductor is $0$.

The self-inductance of a straight conductor is

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