The sequence of reagents required to convert | vedclass

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(A) The conversion of ethyl bromide $(CH_3CH_2Br)$ to propanal $(CH_3CH_2CHO)$ involves the following steps:$1$. Reaction of ethyl bromide with silver

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$CH_3COOAg, DIBAL-H, H_2O$

Vedclass · Answer

(A) The conversion of ethyl bromide $(CH_3CH_2Br)$ to propanal $(CH_3CH_2CHO)$ involves the following steps:$1$. Reaction of ethyl bromide with silver acetate $(CH_3COOAg)$ to form ethyl ethanoate $(CH_3COOCH_2CH_3)$:$CH_3COOAg + CH_3CH_2Br \rightarrow CH_3COOCH_2CH_3 + AgBr \downarrow$$2$. Reduction of the ester (ethyl ethanoate) to an aldehyde using $DIBAL-H$ (Diisobutylaluminium hydride) followed by hydrolysis $(H_2O)$:$CH_3COOCH_2CH_3 \xrightarrow{DIBAL-H, H_2O} CH_3CH_2CHO$Thus,the correct sequence of reagents is $CH_3COOAg, DIBAL-H, H_2O$.

The sequence of reagents required to convert ethyl bromide to propanal is

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