The shape of XeO_2F_2 molecule is | vedclass

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(D) The central atom $Xe$ has $8$ valence electrons.It forms $2$ double bonds with $O$ atoms and $2$ single bonds with $F$ atoms,utilizing $6$ electro

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see-saw

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(D) The central atom $Xe$ has $8$ valence electrons.It forms $2$ double bonds with $O$ atoms and $2$ single bonds with $F$ atoms,utilizing $6$ electrons.This leaves $1$ lone pair on the $Xe$ atom.The total number of electron pairs around $Xe$ is $4$ (bonding pairs) $+ 1$ (lone pair) $= 5$.According to $VSEPR$ theory,$5$ electron pairs correspond to a trigonal bipyramidal electron geometry.With one lone pair occupying an equatorial position,the molecular shape is see-saw.

The shape of $XeO_2F_2$ molecule is

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