The shapes of BrF_5 and XeF_4,respectively ar | vedclass

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(D) For $BrF_5$: The central atom $Br$ has $7$ valence electrons. It forms $5$ bonds with $F$ atoms and has $1$ lone pair. The steric number is $5 + 1

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square pyramid,square planar

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(D) For $BrF_5$: The central atom $Br$ has $7$ valence electrons. It forms $5$ bonds with $F$ atoms and has $1$ lone pair. The steric number is $5 + 1 = 6$,which corresponds to $sp^3d^2$ hybridisation. Due to $1$ lone pair,the geometry is octahedral,but the shape is square pyramidal.For $XeF_4$: The central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms and has $2$ lone pairs. The steric number is $4 + 2 = 6$,which corresponds to $sp^3d^2$ hybridisation. Due to $2$ lone pairs at axial positions,the shape is square planar.

$S_8$	$A$
$P_4$	$B$
$S_6$	$C$
$O_3$	$D$

The shapes of $BrF_5$ and $XeF_4$,respectively are

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