The silicate anion in the mineral kinoite is | vedclass

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Question

(C) chain of three $SiO_4$ tetrahedra sharing corners has the formula $[Si_3O_{10}]^{8-}$.To balance this charge,we need $8$ units of positive charge.

Vedclass · Accepted Answer

$Ca_2Cu_2Si_3O_{10} \cdot 2H_2O$

Vedclass · Answer

(C) chain of three $SiO_4$ tetrahedra sharing corners has the formula $[Si_3O_{10}]^{8-}$.To balance this charge,we need $8$ units of positive charge.The mineral contains $Ca^{2+}$,$Cu^{2+}$,and $H_2O$ in a $1:1:1$ ratio.Let the number of formula units be $x$. The total charge is $x(Ca^{2+} + Cu^{2+}) = x(2+2) = 4x$.For $4x = 8$,we get $x = 2$.Thus,the formula is $Ca_2Cu_2Si_3O_{10} \cdot 2H_2O$.

The silicate anion in the mineral kinoite is a chain of three $SiO_4$ tetrahedra that share corners with adjacent tetrahedra. The mineral also contains $Ca^{2+}$ ions,$Cu^{2+}$ ions,and water molecules in a $1 : 1 : 1$ ratio. The mineral is represented as:

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