The slope of the graph as shown in the figure | vedclass

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Question

(B) The slope of a curve at any point is given by the tangent of the angle $	heta$ that the tangent line at that point makes with the positive $x$-ax

Vedclass · Accepted Answer

$m_1 < m_2 < m_3$

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(B) The slope of a curve at any point is given by the tangent of the angle $	heta$ that the tangent line at that point makes with the positive $x$-axis,i.e.,$m = 	an 	heta$.As we move along the curve from point $1$ to point $3$,the tangent line becomes steeper.This means the angle $	heta$ that the tangent makes with the positive $x$-axis increases as we move from point $1$ to point $3$ (i.e.,$	heta_1 Since the function $	an 	heta$ is an increasing function for $0^\circ Therefore,$m_1 < m_2 < m_3$.

The slope of the graph as shown in the figure at points $1, 2$ and $3$ is $m_1, m_2$ and $m_3$ respectively. Then:

Similar Questions

Which of the following relation$(s)$ is/are correct?
$(A)\ \sin (90^{\circ}+\theta)=\cos (-\theta)$
$(B)\ \sin (180^{\circ}-\theta)=\cos (90^{\circ}-\theta)$
$(C)\ \sin (360^{\circ}-\theta)=\cos (360^{\circ}-\theta)$
$(D)\ \sin (180^{\circ}+\theta)=\cos (90^{\circ}-\theta)$

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