Difficult
The solubility of $N_2$ gas in water at $25 \text{ }^\circ\text{C}$ and $1 \text{ bar}$ is $6.85 \times 10^{-4} \text{ mol L}^{-1}$. Calculate the solubility of $N_2$ gas in water at the same temperature when the partial pressure of $N_2$ is $0.70 \text{ bar}$.
- A$4.80 \times 10^{-4} \text{ mol L}^{-1}$
- B$6.85 \times 10^{-4} \text{ mol L}^{-1}$
- C$7.95 \times 10^{-4} \text{ mol L}^{-1}$
- D$8.75 \times 10^{-4} \text{ mol L}^{-1}$
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Henry's law constants for $O_2$ and $N_2$ are $K_{O_2} = 3.3 \times 10^7 \ atm$ and $K_{N_2} = 6.51 \times 10^7 \ atm$. Calculate the ratio of $\frac{X_{O_2}}{X_{N_2}}$,i.e.,the ratio of mole fractions of $O_2$ and $N_2$ dissolved in water at $25 \ ^\circ C$ from air. (Assume air contains $20 \%$ $O_2$ and $80 \%$ $N_2$ by volume).
Medium
View SolutionThe values of the Henry's law constant of $Ar$,$CO_{2}$,$CH_{4}$ and $O_{2}$ in water at $25^{\circ} C$ are $40.30$,$1.67$,$0.41$ and $34.86 \ kbar$,respectively. The order of their solubility in water at the same temperature and pressure is
MediumKVPY 2019
View SolutionGiven below are two statements:
Statement $I$: The Henry's law constant $K_{H}$ is constant with respect to variations in solution's concentration over the range for which the solution is ideally dilute.
Statement $II$: $K_{H}$ does not differ for the same solute in different solvents.
In the light of the above statements, choose the correct answer from the options.
Statement $I$: The Henry's law constant $K_{H}$ is constant with respect to variations in solution's concentration over the range for which the solution is ideally dilute.
Statement $II$: $K_{H}$ does not differ for the same solute in different solvents.
In the light of the above statements, choose the correct answer from the options.
DifficultJEE MAIN 2026
View SolutionDry air contains $79 \% \,N_2$ and $21 \% \,O_2$. At $T \,K$, if Henry's law constants for $N_2$ and $O_2$ in water are $8.57 \times 10^4 \,atm$ and $4.56 \times 10^4 \,atm$ respectively, the ratio of mole fractions of $N_2$ and $O_2$ dissolved in water at $1 \,atm$ is
Rank the following solvents in decreasing order of their ability to dissolve the given solute (naphthalene).
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