The solubility of silver chromate in $0.01 \, M$ $K_2CrO_4$ is $2 \times 10^{-8} \, mol \, dm^{-3}$. The solubility product of silver chromate will be

  • A
    $8 \times 10^{-24}$
  • B
    $16 \times 10^{-24}$
  • C
    $1.6 \times 10^{-18}$
  • D
    $16 \times 10^{-18}$

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$[$Given: $\sqrt{2}=1.41]$

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