The solubility product constant K_{sp} of Mg( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The dissolution equilibrium for $Mg(OH)_2$ is given by: $Mg(OH)_2(s) \rightleftharpoons Mg^{2+}(aq) + 2OH^-(aq)$.The solubility product expression

Vedclass · Accepted Answer

$3.0 	imes 10^{-5} \ M$

Vedclass · Answer

(D) The dissolution equilibrium for $Mg(OH)_2$ is given by: $Mg(OH)_2(s) ightleftharpoons Mg^{2+}(aq) + 2OH^-(aq)$.The solubility product expression is $K_{sp} = [Mg^{2+}][OH^-]^2$.Given $K_{sp} = 9.0 	imes 10^{-12}$ and $[Mg^{2+}] = 0.010 \ M$.Substituting these values into the expression: $9.0 	imes 10^{-12} = (0.010)[OH^-]^2$.Solving for $[OH^-]^2$: $[OH^-]^2 = \frac{9.0 	imes 10^{-12}}{0.010} = 9.0 	imes 10^{-10}$.Taking the square root: $[OH^-] = \sqrt{9.0 	imes 10^{-10}} = 3.0 	imes 10^{-5} \ M$.Therefore,the maximum hydroxide ion concentration is $3.0 	imes 10^{-5} \ M$.

The solubility product constant $K_{sp}$ of $Mg(OH)_2$ is $9.0 \times 10^{-12}.$ If a solution is $0.010 \ M$ with respect to $Mg^{2+}$ ion,what is the maximum hydroxide ion concentration which could be present without causing the precipitation of $Mg(OH)_2$?

Similar Questions

Which of the following pairs of ions would be expected to form a precipitate when their solutions are mixed?

The $K_{sp}$ for $BaSO_4$ at $25\ ^\circ C$ is $1.1 \times 10^{-10}$. To make the new solubility equal to $1.1 \times 10^{-8} \ M$,it is necessary to use a solution of $Na_2SO_4$ of the following concentration (in $M$):

The molar solubility of $PbI_2$ in $0.2 \ M \ Pb(NO_3)_2$ solution in terms of solubility product of $PbI_2$ is

Which of the following sulphides has the lowest solubility product?

Solubility product $(K_{sp})$ of salts of type $MX$,$MX_2$,and $M_3X$ at temperature $T$ are $4 \times 10^{-8}$,$3.2 \times 10^{-14}$,and $2.7 \times 10^{-15}$ respectively. The solubility of the salts at temperature $T$ are in the order:

Vedclass Test Series

Exam Paper Generator

Online Exam Module