The solubility product of $BaSO_4$ is $1.3 \times 10^{-9}$. The solubility of this salt in pure water will be
- A$1.69 \times 10^{-9} \ mol \ L^{-1}$
- B$1.69 \times 10^{-18} \ mol \ L^{-1}$
- C$3.6 \times 10^{-18} \ mol \ L^{-1}$
- D$3.6 \times 10^{-5} \ mol \ L^{-1}$
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