The solution of x+y-1=0 and 2x+2y-2=0 is .... | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given equations are:$x + y - 1 = 0$  --- $(1)$$2x + 2y - 2 = 0$ --- $(2)$Divide equation $(2)$ by $2$:$x + y - 1 = 0$Since both equations are iden

Vedclass · Accepted Answer

an infinite set

Vedclass · Answer

(C) Given equations are:$x + y - 1 = 0$  --- $(1)$$2x + 2y - 2 = 0$ --- $(2)$Divide equation $(2)$ by $2$:$x + y - 1 = 0$Since both equations are identical,they represent the same line.For a system of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$,if $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$,the system has infinitely many solutions.Here,$\frac{1}{2} = \frac{1}{2} = \frac{-1}{-2} = \frac{1}{2}$.Therefore,the system has infinitely many solutions,which corresponds to an infinite set.

The solution of $x+y-1=0$ and $2x+2y-2=0$ is ............

Similar Questions

Solve the following pairs of equations by the method of elimination:
$4x - 3y = 5$
$\frac{5}{2}x - y = 4$

One equation of a pair of dependent linear equations is $-5x + 7y = 2$. The second equation can be

Determine,algebraically,the vertices of the triangle formed by the lines $5x - y = 5$,$x + 2y = 1$,and $6x + y = 17$.

$x$ is larger in two numbers $x$ and $y$. Two times the larger number is $4$ more than five times the smaller number. The equation form of this data is $\ldots \ldots \ldots \ldots$

If the following pair of equations is consistent (unique solution),then find the value of $k$:
$x - ky = 2$
$3x + 2y = -5$

Vedclass Test Series

Exam Paper Generator

Online Exam Module