The specific charge of a proton is 9.6 times | vedclass

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(D) The specific charge is defined as the ratio of charge to mass,$\frac{q}{m}$.For a proton $(p)$,the charge is $e$ and the mass is $m_p$.For an $\al

Vedclass · Accepted Answer

$4.8 	imes 10^7 \ C \ kg^{-1}$

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(D) The specific charge is defined as the ratio of charge to mass,$\frac{q}{m}$.For a proton $(p)$,the charge is $e$ and the mass is $m_p$.For an $\alpha$-particle,the charge is $2e$ and the mass is $4m_p$.Therefore,$(\frac{q}{m})_{\alpha} = \frac{2e}{4m_p} = \frac{1}{2} (\frac{e}{m_p}) = \frac{1}{2} (\frac{q}{m})_p$.Given $(\frac{q}{m})_p = 9.6 	imes 10^7 \ C \ kg^{-1}$,the specific charge for an $\alpha$-particle is $\frac{1}{2} 	imes 9.6 	imes 10^7 \ C \ kg^{-1} = 4.8 	imes 10^7 \ C \ kg^{-1}$.

The specific charge of a proton is $9.6 \times 10^7 \ C \ kg^{-1}$. What will be the specific charge for an $\alpha$-particle?

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