The specific conductance $(\kappa)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation of acetic acid is [Given equivalent conductance at infinite dilution of $H^{+} = 349.1 \ S \ cm^{2} \ mol^{-1}$ and $CH_{3}COO^{-} = 40.9 \ S \ cm^{2} \ mol^{-1}$]

  • A
    $0.021$
  • B
    $0.21$
  • C
    $0.012$
  • D
    $0.12$

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Similar Questions

At $298 \ K$ the molar conductivities at infinite dilution $(\Lambda_m^{\circ})$ of $NH_4Cl, KOH$ and $KCl$ are $152.8, 272.6$ and $149.8 \ S \ cm^2 \ mol^{-1}$ respectively. The $\Lambda_m^{\circ}$ of $NH_4OH$ in $S \ cm^2 \ mol^{-1}$ and $\%$ dissociation of $0.01 \ M \ NH_4OH$ with $\Lambda_m = 25.1 \ S \ cm^2 \ mol^{-1}$ at the same temperature are

Conductivity of a saturated solution of a sparingly soluble salt $AB$ at $298 \ K$ is $1.85 \times 10^{-5} \ S \ m^{-1}$. Solubility product of the salt $AB$ at $298 \ K$ is. Given $\Lambda_{m}^{\circ}(AB) = 140 \times 10^{-4} \ S \ m^{2} \ mol^{-1}$.

What is the $SI$ unit of conductivity?

$A$ conductivity cell shows a resistance of $600 \ \Omega$. If the conductivity of $0.01 \ M \ KCl$ is $0.0015 \ \Omega^{-1} \ cm^{-1}$,what is the cell constant (in $cm^{-1}$)?

The molar conductivity of $KCl$ solutions at different concentrations at $298 \ K$ is given below:
$c / mol \ L^{-1}$$\Lambda_m / S \ cm^2 \ mol^{-1}$
$0.000198$$148.61$
$0.000309$$148.29$
$0.000521$$147.81$
$0.000989$$147.09$

Show that a plot of $\Lambda_m$ versus $c^{1/2}$ is a straight line. Determine the values of $\Lambda_m^o$ and $A$ for $KCl$.

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