The specific conductance of a $0.1 \ N \ KCl$ solution at $23 \ ^oC$ is $0.012 \ \Omega^{-1} \ cm^{-1}$. The resistance of a cell containing the solution at the same temperature was found to be $55 \ \Omega$. The cell constant will be .............. $cm^{-1}$.

  • A
    $0.142$
  • B
    $0.66$
  • C
    $0.918$
  • D
    $1.12$

Explore More

Similar Questions

The molar conductivity for electrolytes $A$ and $B$ are plotted against $C^{1/2}$ as shown below. Electrolytes $A$ and $B$ respectively are:

How does electrolytic conduction differ from metallic conduction?

At a particular temperature, the ratio of equivalent conductance to specific conductance of a $0.01 \ N$ $NaCl$ solution is

The resistance of $0.01 \ N$ $NaCl$ solution at $25 \ ^oC$ is $200 \ \Omega$. The cell constant of the conductivity cell is $1 \ cm^{-1}$. The equivalent conductance is:

What is the molar conductivity of a $0.05 \ M$ solution of sodium hydroxide,if its conductivity is $0.0118 \ S \ cm^{-1}$ at $298 \ K$?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo