The speeds of A and B are in the ratio of 3: | vedclass

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(A) Let the speed of $A$ be $3x$ and the speed of $B$ be $4x$.Since the distance $D$ is the same for both, we have $D = 	ext{speed} 	imes 	ext{time

Vedclass · Accepted Answer

$1\frac{1}{3} \, h$

Vedclass · Answer

(A) Let the speed of $A$ be $3x$ and the speed of $B$ be $4x$.Since the distance $D$ is the same for both, we have $D = 	ext{speed} 	imes 	ext{time}$.Let $t$ be the time taken by $B$ in hours. Then the time taken by $A$ is $(t + \frac{20}{60}) \, h = (t + \frac{1}{3}) \, h$.Equating the distances: $3x(t + \frac{1}{3}) = 4x(t)$.Dividing both sides by $x$: $3(t + \frac{1}{3}) = 4t$.$3t + 1 = 4t \Rightarrow t = 1 \, h$.Therefore, the time taken by $A$ is $t + \frac{1}{3} = 1 + \frac{1}{3} = 1\frac{1}{3} \, h$.

The speeds of $A$ and $B$ are in the ratio of $3: 4$. $A$ takes $20 \, min$ more than $B$ to reach a destination. Find the time in which $A$ reaches the destination.

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