The structure of the product (Z) in the react | vedclass

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(C) $1.$ Acetylene reacts with $NaNH_2$ to form sodium acetylide: $HC \equiv CH + NaNH_2 \rightarrow HC \equiv C^{-}Na^{+} + NH_3$. $2.$ Sodium acetyl

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$CH_3-CO-C(OH)(CH_3)_2$

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(C) $1.$ Acetylene reacts with $NaNH_2$ to form sodium acetylide: $HC \equiv CH + NaNH_2 \rightarrow HC \equiv C^{-}Na^{+} + NH_3$. $2.$ Sodium acetylide reacts with acetone $(CH_3COCH_3)$ followed by acidification to form $X$: $HC \equiv C^{-}Na^{+} + CH_3COCH_3 \xrightarrow{H^{+}} HC \equiv C-C(CH_3)_2OH$ ($2$-methylbut-$3$-yn-$2$-ol). $3.$ Hydration of the alkyne $X$ using $Hg^{2+}/H_2O/H^{+}$ follows Markovnikov's addition to form an enol,which tautomerizes to the ketone $Z$: $HC \equiv C-C(CH_3)_2OH \xrightarrow{Hg^{2+}, H_2O, H^{+}} CH_3-CO-C(OH)(CH_3)_2$ ($3$-hydroxy-$3$-methylbutan-$2$-one). Therefore,the structure of $Z$ is $CH_3-CO-C(OH)(CH_3)_2$.

The structure of the product $(Z)$ in the reactions given below is:
$HC \equiv CH$ $\xrightarrow{NaNH_2, CH_3COCH_3, H^{+}} X$ $\xrightarrow{Hg^{2+}, H_3O^{+}, H_2O} Z$

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The structure of the product $(Z)$ in the reactions given below is: $HC \equiv CH$ $\xrightarrow{NaNH_2, CH_3COCH_3, H^{+}} X$ $\xrightarrow{Hg^{2+}, H_3O^{+}, H_2O} Z$