The sum and difference of the reciprocals of the ages of a son and father are respectively $\frac{5}{40}$ and $\frac{3}{40}$. Represent this as a pair of linear equations in two variables,where $x$ is the age of the son and $y$ is the age of the father.

• A
  $\frac{1}{x} + \frac{1}{y} = \frac{5}{40}, \frac{1}{x} - \frac{1}{y} = \frac{3}{40}$
• B
  $\frac{1}{x} + \frac{1}{y} = \frac{3}{40}, \frac{1}{x} - \frac{1}{y} = \frac{5}{40}$
• C
  $x + y = \frac{5}{40}, x - y = \frac{3}{40}$
• D
  $\frac{1}{x} + \frac{1}{y} = \frac{40}{5}, \frac{1}{x} - \frac{1}{y} = \frac{40}{3}$