The sum of $IE_1 + IE_2$ and $IE_3 + IE_4$ for elements $P$ and $Q$ are given below:
Element $IE_1 + IE_2$ $(kJ/mol)$ $IE_3 + IE_4$ $(kJ/mol)$
$P$ $2.45$ $8.82$
$Q$ $2.85$ $6.11$

Then,according to the given information,the incorrect statement$(s)$ is/are:

  • A
    $P^{2+}$ is more stable than $Q^{2+}$
  • B
    $P^{4+}$ is more stable than $Q^{4+}$
  • C
    $P^{4+}$ is less stable than $Q^{4+}$
  • D
    Both $(A)$ and $(C)$

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Similar Questions

Arrange the following elements in increasing order of first ionization enthalpy:
$Li, Be, B, C, N$
Choose the correct answer from the options given below:

The correct order of ionisation energy of $C$,$N$,$O$,and $F$ is

Match the following List-$I$ and List-$II$ and select the correct answer using the codes given below.
List-$I$ (Successive Ionization Enthalpy) $\left( kJ \, mol^{-1} \right)$ List-$II$
Element$IE_1$$IE_2$$IE_3$CodeElement
$1$$2080$$3963$$6130$$(a)$$H$
$2$$520$$7297$$11810$$(b)$$Li$
$3$$900$$1758$$14810$$(c)$$Be$
$4$$800$$2428$$3660$$(d)$$B$
----$(e)$$Ne$

The ionization energy of boron is less than that of beryllium because

How many ionisation energies can carbon have?

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