When two dice are thrown,what is the probabil | vedclass

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(C) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.The sum of the numbers on the two dice is even if both

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$\frac{1}{2}$

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(C) When two dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.The sum of the numbers on the two dice is even if both numbers are even or both numbers are odd.Case $1$: Both numbers are odd. The possible outcomes are $(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5)$. There are $9$ such outcomes.Case $2$: Both numbers are even. The possible outcomes are $(2,2), (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6)$. There are $9$ such outcomes.Total favorable outcomes $n(E) = 9 + 9 = 18$.Therefore,the required probability $P(E) = \frac{n(E)}{n(S)} = \frac{18}{36} = \frac{1}{2}$.

When two dice are thrown,what is the probability that the sum of the numbers appearing on them is an even number?

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