The sum of the ages of a father and son is 45 | vedclass

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(B) Let the father's present age be $x$ years.Then,the son's present age is $(45 - x)$ years.$5$ years ago,the father's age was $(x - 5)$ years and th

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(B) Let the father's present age be $x$ years.Then,the son's present age is $(45 - x)$ years.$5$ years ago,the father's age was $(x - 5)$ years and the son's age was $(45 - x - 5) = (40 - x)$ years.According to the problem,the product of their ages $5$ years ago was $4$ times the father's age at that time:$(x - 5)(40 - x) = 4(x - 5)$Since $x$ cannot be $5$ (as the son's age would be $40$ and the father's age $5$,which is impossible for a father-son relationship in this context),we can divide both sides by $(x - 5)$:$40 - x = 4$$x = 40 - 4 = 36$Therefore,the present age of the father is $36$ years.

The sum of the ages of a father and son is $45$ years. $5$ years ago,the product of their ages was four times the father's age at that time. The present age of the father is (in years):

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