The sum of the radius of the base and the hei | vedclass

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(A) Given: $r + h = 37 \, m$ and Total Surface Area $= 2 \pi r(r + h) = 1628 \, m^2$.Substituting the value of $(r + h)$ in the surface area formula:$

Vedclass · Accepted Answer

$4620$

Vedclass · Answer

(A) Given: $r + h = 37 \, m$ and Total Surface Area $= 2 \pi r(r + h) = 1628 \, m^2$.Substituting the value of $(r + h)$ in the surface area formula:$2 	imes \frac{22}{7} 	imes r 	imes 37 = 1628$$r = \frac{1628 	imes 7}{44 	imes 37} = \frac{1628}{1628} 	imes 7 = 7 \, m$.Now,find the height $h$:$h = 37 - r = 37 - 7 = 30 \, m$.The volume of the cylinder is given by $V = \pi r^2 h$.$V = \frac{22}{7} 	imes 7 	imes 7 	imes 30 = 22 	imes 7 	imes 30 = 4620 \, m^3$.

The sum of the radius of the base and the height of a solid cylinder is $37 \, m$. If the total surface area of the cylinder is $1628 \, m^2$,find the volume (in $m^3$).

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