The sum of two numbers is frac{28}{25} of the | vedclass

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Question

(A) Let the first number be $x$ and the second number be $y$.According to the problem,the sum of the two numbers is $\frac{28}{25}$ of the first numbe

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) Let the first number be $x$ and the second number be $y$.According to the problem,the sum of the two numbers is $\frac{28}{25}$ of the first number:$x + y = \frac{28}{25}x$Subtract $x$ from both sides to find $y$:$y = \frac{28}{25}x - x$$y = \left(\frac{28}{25} - 1ight)x$$y = \left(\frac{28 - 25}{25}ight)x = \frac{3}{25}x$To find what percent the second number $(y)$ is of the first number $(x)$,we calculate:$\left(\frac{y}{x}ight) 	imes 100 = \left(\frac{3/25x}{x}ight) 	imes 100$$= \frac{3}{25} 	imes 100 = 3 	imes 4 = 12\%$Thus,the second number is $12\%$ of the first number.

The sum of two numbers is $\frac{28}{25}$ of the first number. The second number is what percent of the first (in $\%$)?

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