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(B) According to Einstein's photoelectric equation: $K_{max} = E - W_0$,where $E$ is the energy of the incident photon and $W_0$ is the work function

Vedclass · Accepted Answer

$1.42$

Vedclass · Answer

(B) According to Einstein's photoelectric equation: $K_{max} = E - W_0$,where $E$ is the energy of the incident photon and $W_0$ is the work function of the metal.The energy of the incident photon is given by: $E = \frac{hc}{\lambda} = \frac{1240\, eV\, nm}{400\, nm} = 3.1\, eV$.Given that the maximum kinetic energy $K_{max} = 1.68\, eV$,we can substitute these values into the equation:$1.68\, eV = 3.1\, eV - W_0$.Rearranging to solve for the work function $W_0$:$W_0 = 3.1\, eV - 1.68\, eV = 1.42\, eV$.

The surface of a metal is illuminated with light of $400\, nm$. The maximum kinetic energy of the ejected photoelectrons was found to be $1.68\, eV$. The work function of the metal is.......$eV$ $(hc = 1240\, eV\, nm)$.

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