The table below gives the percentage distribution of female teachers in the primary schools of rural areas of various states and union territories $(U.T.)$ of India. Find the mean percentage of female teachers by all the three methods discussed in this section.
Percentage of female teachers $15$-$25$ $25$-$35$ $35$-$45$ $45$-$55$ $55$-$65$ $65$-$75$ $75$-$85$ Number of States/$U$.$T$. $6$ $11$ $7$ $4$ $4$ $2$ $1$
| Percentage of female teachers | $15$-$25$ | $25$-$35$ | $35$-$45$ | $45$-$55$ | $55$-$65$ | $65$-$75$ | $75$-$85$ |
| Number of States/$U$.$T$. | $6$ | $11$ | $7$ | $4$ | $4$ | $2$ | $1$ |
- A$45.78$
- B$39.71$
- C$56.5$
- D$47.30$
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Similar Questions
The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
Number of students per teacher Number of states/$U$.$T$. $15-20$ $3$ $20-25$ $8$ $25-30$ $9$ $30-35$ $10$ $35-40$ $3$ $40-45$ $0$ $45-50$ $0$ $50-55$ $2$
| Number of students per teacher | Number of states/$U$.$T$. |
| $15-20$ | $3$ |
| $20-25$ | $8$ |
| $25-30$ | $9$ |
| $30-35$ | $10$ |
| $35-40$ | $3$ |
| $40-45$ | $0$ |
| $45-50$ | $0$ |
| $50-55$ | $2$ |
Medium
View SolutionThe lengths of $40$ leaves of a plant are measured correct to the nearest millimetre,and the data obtained is represented in the following table:
Length (in mm) Number of leaves $118-126$ $3$ $127-135$ $5$ $136-144$ $9$ $145-153$ $12$ $154-162$ $5$ $163-171$ $4$ $172-180$ $2$
Find the median length of the leaves.
| Length (in mm) | Number of leaves |
| $118-126$ | $3$ |
| $127-135$ | $5$ |
| $136-144$ | $9$ |
| $145-153$ | $12$ |
| $154-162$ | $5$ |
| $163-171$ | $4$ |
| $172-180$ | $2$ |
Find the median length of the leaves.
Medium
View Solution$A$ life insurance agent found the following data for the distribution of ages of $100$ policy holders. Calculate the median age,if policies are given only to persons having age $18$ years onwards but less than $60$ years.
Age (in years) Number of policy holders Below $20$ $2$ Below $25$ $6$ Below $30$ $24$ Below $35$ $45$ Below $40$ $78$ Below $45$ $89$ Below $50$ $92$ Below $55$ $98$ Below $60$ $100$
| Age (in years) | Number of policy holders |
| Below $20$ | $2$ |
| Below $25$ | $6$ |
| Below $30$ | $24$ |
| Below $35$ | $45$ |
| Below $40$ | $78$ |
| Below $45$ | $89$ |
| Below $50$ | $92$ |
| Below $55$ | $98$ |
| Below $60$ | $100$ |
Difficult
View SolutionThe following table gives the distribution of the lifetime of $400$ neon lamps:
Life time (in hours) Number of lamps $1500-2000$ $14$ $2000-2500$ $56$ $2500-3000$ $60$ $3000-3500$ $86$ $3500-4000$ $74$ $4000-4500$ $62$ $4500-5000$ $48$
Find the median lifetime of a lamp.
| Life time (in hours) | Number of lamps |
| $1500-2000$ | $14$ |
| $2000-2500$ | $56$ |
| $2500-3000$ | $60$ |
| $3000-3500$ | $86$ |
| $3500-4000$ | $74$ |
| $4000-4500$ | $62$ |
| $4500-5000$ | $48$ |
Find the median lifetime of a lamp.
Difficult
View Solution$A$ student noted the number of cars passing through a spot on a road for $100$ periods each of $3\, \text{minutes}$ and summarized it in the table given below. Find the mode of the data:
Number of cars $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $7$ $14$ $13$ $12$ $20$ $11$ $15$ $8$
| Number of cars | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $7$ | $14$ | $13$ | $12$ | $20$ | $11$ | $15$ | $8$ |
Medium
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