The temperature of 5 moles of a gas which was | vedclass

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(C) For a process at constant volume,the heat supplied $(\Delta Q)_V$ is equal to the change in internal energy $(\Delta U)$.Given: $\Delta U = 80 \ J

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(C) For a process at constant volume,the heat supplied $(\Delta Q)_V$ is equal to the change in internal energy $(\Delta U)$.Given: $\Delta U = 80 \ J$,$\Delta T = 120^{\circ}C - 100^{\circ}C = 20 \ K$.The total heat capacity at constant volume $(C_{total})$ is defined as $C_{total} = \frac{(\Delta Q)_V}{\Delta T}$.Since $(\Delta Q)_V = \Delta U$,we have $C_{total} = \frac{\Delta U}{\Delta T}$.Substituting the values: $C_{total} = \frac{80 \ J}{20 \ K} = 4 \ J/K$.

The temperature of $5$ moles of a gas which was held at constant volume was changed from $100^{\circ}C$ to $120^{\circ}C$. The change in internal energy was found to be $80$ Joules. The total heat capacity of the gas at constant volume will be equal to ...... $J/K$.

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