Easy
The temperature of an ideal gas is increased from $140 \,K$ to $560 \,K$. If the r.m.s. speed of gas molecules is $v$ at $140 \,K$, then at $560 \,K$, the r.m.s. speed becomes:
- A$4 v$
- B$\frac{v}{4}$
- C$\frac{v}{2}$
- D$2 v$
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