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Question

(B) According to Stefan-Boltzmann Law,the energy emitted per second $P$ is proportional to the fourth power of the absolute temperature,i.e.,$P \propt

Vedclass · Accepted Answer

$1:81$

Vedclass · Answer

(B) According to Stefan-Boltzmann Law,the energy emitted per second $P$ is proportional to the fourth power of the absolute temperature,i.e.,$P \propto T^4$.First,convert the temperatures from Celsius to Kelvin:$T_1 = -73 + 273 = 200 \ K$$T_2 = 327 + 273 = 600 \ K$Now,find the ratio of energy emitted per second:$\frac{P_1}{P_2} = \left( \frac{T_1}{T_2} \right)^4$$\frac{P_1}{P_2} = \left( \frac{200}{600} \right)^4$$\frac{P_1}{P_2} = \left( \frac{1}{3} \right)^4 = \frac{1}{81}$Thus,the ratio of energy emitted per second is $1:81$.

The temperature of a body is increased from $-73^{\circ}C$ to $327^{\circ}C$. The ratio of energy emitted per second is:

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