The test to differentiate between $\text{pentan-2-one}$ and $\text{pentan-3-one}$ is

Explain the Cannizzaro reaction.

$CH_3-CH=CH-CH_2OH \xrightarrow{PCC} CH_3-CH=CH-CHO$
What is the change in hybridisation at $C-1$ in the above reaction?

Compounds $A$ and $B$,both were treated with $NaOH$,producing a single compound $C$. Identify compound $C$.

Match List-$I$ with List-$II$ and then select the correct answer from the codes given below that list.

List-$I$	List-$II$
$A$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$	$a$. Gattermann-Koch reaction
$B$. $C_6H_5CH_3 \xrightarrow{CrO_2Cl_2} C_6H_5CHO$	$b$. Etard reaction
$C$. $C_6H_5CH_2Br + CH_3Br \xrightarrow{Na/ether} C_6H_5CH_2CH_3$	$c$. Wurtz-Fittig reaction
$D$. $C_6H_6 + (CH_3)_2C = CH_2 \xrightarrow{H_2SO_4} C_6H_5C(CH_3)_3$	$d$. Friedel-Crafts alkylation

Given below are two statements:
Statement $I$: $H_2N-CO-CH_2-CH_2-CO-CH_3$ under Clemmensen reduction conditions will give $HOOC-(CH_2)_3-CH_3$.
Statement $II$: $CH_3-CH(CH_3)-CH_2-CH(Cl)-CO-CH_3$ under Wolff-Kishner reduction conditions will give $CH_3-CH(CH_3)-CH_2-CH(Cl)-CH_2-CH_3$.
In the light of the above statements,choose the correct answer from the options given below: