The time period of a freely suspended magnet is $4 \ s$. If it is broken in length into two equal parts and one part is suspended in the same way,then its time period will be: (in $s$)

  • A
    $4$
  • B
    $2$
  • C
    $0.5$
  • D
    $0.25$

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$A$ bar magnet $AB$ is cut into two equal parts as shown in the figure. One part is kept over the other so that the pole $C_{2}$ is above $C_{1}$. If $M$ is the magnetic moment of the original magnet,the magnetic moment of the combination so formed is

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