The time period of a simple pendulum on a freely moving artificial satellite is

$A$ man measures the period of a simple pendulum inside a stationary lift and finds it to be $T$ seconds. If the lift accelerates upwards with an acceleration of $\frac{g}{4}$,then the period of the pendulum will be

$A$ simple pendulum with length $100\,cm$ and bob of mass $250\,g$ is executing $S$.$H$.$M$. of amplitude $10\,cm$. The maximum tension in the string is found to be $\frac{x}{40}\,N$. The value of $x$ is $..........$.

The period of small oscillation of a simple pendulum is $T$. The ratio of the density of the liquid to the density of the material of the bob is $\rho$ (where $\rho < 1$). When the bob is immersed in the liquid,the new time period of small oscillation will be:

$A$ light balloon filled with helium of density $\rho_{He}$ is tied to a long light string of length $l$ and the string is attached to the ground. If the balloon is displaced slightly in the horizontal direction from the equilibrium and released,then:

The length of a seconds pendulum is $1 \,m$ on the earth. If the mass and diameter of a planet are double that of the earth, then the length of the seconds pendulum on the planet will be: (in $\,m$)