The torque of a force overrightarrow{F} = -3h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The torque $\overrightarrow{	au}$ is given by the cross product of the position vector $\overrightarrow{r}$ and the force vector $\overrightarrow

Vedclass · Accepted Answer

$14\hat{i} - 38\hat{j} + 16\hat{k}$

Vedclass · Answer

(A) The torque $\overrightarrow{	au}$ is given by the cross product of the position vector $\overrightarrow{r}$ and the force vector $\overrightarrow{F}$.$\overrightarrow{	au} = \overrightarrow{r} 	imes \overrightarrow{F}$$\overrightarrow{	au} = (7\hat{i} + 3\hat{j} + \hat{k}) 	imes (-3\hat{i} + \hat{j} + 5\hat{k})$Using the determinant method for the cross product:$\overrightarrow{	au} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 7 & 3 & 1 \ -3 & 1 & 5 \end{vmatrix}$$\overrightarrow{	au} = \hat{i}(3 	imes 5 - 1 	imes 1) - \hat{j}(7 	imes 5 - 1 	imes (-3)) + \hat{k}(7 	imes 1 - 3 	imes (-3))$$\overrightarrow{	au} = \hat{i}(15 - 1) - \hat{j}(35 + 3) + \hat{k}(7 + 9)$$\overrightarrow{	au} = 14\hat{i} - 38\hat{j} + 16\hat{k}$

The torque of a force $\overrightarrow{F} = -3\hat{i} + \hat{j} + 5\hat{k}$ acting at the point $\overrightarrow{r} = 7\hat{i} + 3\hat{j} + \hat{k}$ is:

Similar Questions

$A$ couple produces:

Which physical quantity plays the same role in rotational motion as force does in linear motion?

The rotational motion of a body is caused by:

$A$ triangular plate is shown in the figure. $A$ force $\overrightarrow{F} = 4 \hat{i} - 3 \hat{j}$ is applied at point $P$. The torques at point $P$ with respect to point $O$ and point $Q$ are:

For a particle moving in a circular path under the influence of a central force,the angular momentum remains constant because .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module