The torque required to hold a small circular | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic dipole moment of the coil is given by $M = N A I$. Substituting the given values: $M = 10 	imes (2 	imes 10^{-4} \ m^2) 	imes 0.5

Vedclass · Accepted Answer

$12 \pi 	imes 10^{-7} \ N \ m$

Vedclass · Answer

(A) The magnetic dipole moment of the coil is given by $M = N A I$. Substituting the given values: $M = 10 	imes (2 	imes 10^{-4} \ m^2) 	imes 0.5 \ A = 10^{-3} \ A \ m^2$.The magnetic field inside a long solenoid is given by $B = \mu_0 n I_s$. Substituting the values: $B = (4 \pi 	imes 10^{-7} \ T \ m/A) 	imes (10^3 \ m^{-1}) 	imes (3 \ A) = 12 \pi 	imes 10^{-4} \ T$.The torque on a magnetic dipole in a magnetic field is $	au = M B \sin(	heta)$. Since the axis of the coil is perpendicular to the axis of the solenoid,the angle between the magnetic moment vector and the magnetic field is $	heta = 90^\circ$,so $\sin(90^\circ) = 1$.Therefore,$	au = (10^{-3} \ A \ m^2) 	imes (12 \pi 	imes 10^{-4} \ T) 	imes 1 = 12 \pi 	imes 10^{-7} \ N \ m$.

The torque required to hold a small circular coil of $10$ turns,$2 \times 10^{-4} \ m^2$ area,and carrying $0.5 \ A$ current in the middle of a long solenoid of $10^3$ turns per meter carrying $3 \ A$ current,with its axis perpendicular to the axis of the solenoid,is:

Similar Questions

$A$ single circular loop of radius $1.00 \, m$ carries a current of $10.0 \, mA$. It is placed in a uniform magnetic field of magnitude $0.500 \, T$ that is directed parallel to the plane of the loop as shown in the figure. The magnitude of the torque exerted on the loop by the magnetic field is:

$A$ current-carrying loop is placed in a uniform magnetic field. The torque acting on the loop does not depend upon

$A$ coil in the shape of an equilateral triangle of side $l$ is suspended between the pole pieces of a permanent magnet such that $\vec{B}$ is in the plane of the coil. If due to a current $i$ in the triangle a torque $\tau$ acts on it,the side $l$ of the triangle is

$A$ uniform magnetic field of $0.3 \text{ T}$ is established along the $+z$-direction. $A$ rectangular loop of sides $10 \text{ cm}$ and $5 \text{ cm}$ carries a current of $12 \text{ A}$ and is placed in the $xy$-plane as shown in the figure. The torque acting on the loop is $....... \text{ Nm}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module