The total charge on a uniformly charged spher | vedclass

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(A) For a uniformly charged spherical shell, the electric potential at any point inside the shell is constant and equal to the potential at its surfac

Vedclass · Accepted Answer

$Q / 4\pi\epsilon_0 R$

Vedclass · Answer

(A) For a uniformly charged spherical shell, the electric potential at any point inside the shell is constant and equal to the potential at its surface.The potential at the surface of the shell is given by $V = \frac{1}{4\pi \epsilon_0} \frac{Q}{R}$.Since the distance $r = R/2$ is less than the radius $R$ (i.e.,the point is inside the shell), the electric potential at this point is the same as the potential at the surface.Therefore, the potential at $r = R/2$ is $V = \frac{Q}{4\pi \epsilon_0 R}$.

The total charge on a uniformly charged spherical shell having radius $R$ is $Q$. Then electric potential at a distance $r = R/2$ from the centre of the shell is . . . . . . .

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