The total maximum number of electrons possible in $3d$,$6d$,$5s$,and $4f$ orbitals with $m_l$ (magnetic quantum number) value $-2$ is

What is the electronic configuration of an atom? Explain its method with examples.

An atom of an element contains $29$ electrons and $35$ neutrons. Determine $(i)$ the number of protons and $(ii)$ the electronic configuration of the element.

Given below are two statements:
Statement-$I$: The orbitals having same energy are called as degenerate orbitals.
Statement-$II$: In hydrogen atom,$3p$ and $3d$ orbitals are not degenerate orbitals.
In the light of the above statements,choose the most appropriate answer from the options given.

The electrons,identified by quantum numbers $n$ and $l$ as $(i) n = 4, l = 1$,$(ii) n = 4, l = 0$,$(iii) n = 3, l = 2$,$(iv) n = 3, l = 1$,can be placed in order of increasing energy,from the lowest to highest,as:

Select the correct statements for quantum numbers.
$(i)$ Magnetic quantum number $(m_l)$ gives information about the spatial orientation of orbitals with respect to the standard set of coordinate axes.
$(ii)$ Electron spin quantum number is represented by '$s$' and has values of $\pm \frac{1}{2}$.
$(iii)$ Principal quantum number $(n)$ determines the size of the orbitals and also,to a large extent,the energy of the orbitals.