The total number of sigma and pi-bonds presen | vedclass

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(B) The given compound is methyl $3-$amino$-5-$hydroxybenzoate. To find the total number of $\sigma$ and $\pi$ bonds,we expand the structure: $1$. Ben

Vedclass · Accepted Answer

$\sigma = 21, \pi = 4$

Vedclass · Answer

(B) The given compound is methyl $3-$amino$-5-$hydroxybenzoate. To find the total number of $\sigma$ and $\pi$ bonds,we expand the structure: $1$. Benzene ring: $6$ $C$-$C$ $\sigma$ bonds,$3$ $C$-$C$ $\pi$ bonds,and $3$ $C$-$H$ $\sigma$ bonds. $2$. Amino group $(-NH_2)$: $2$ $N$-$H$ $\sigma$ bonds and $1$ $C$-$N$ $\sigma$ bond. $3$. Hydroxy group $(-OH)$: $1$ $O$-$H$ $\sigma$ bond and $1$ $C$-$O$ $\sigma$ bond. $4$. Ester group $(-COOCH_3)$: $1$ $C$-$C$ $\sigma$ bond,$1$ $C$=$O$ $\pi$ bond,$1$ $C$-$O$ $\sigma$ bond,$1$ $C$-$O$ $\sigma$ bond,$3$ $C$-$H$ $\sigma$ bonds. Total $\pi$ bonds = $3$ (in ring) + $1$ (in $C$=$O$) = $4$. Total $\sigma$ bonds = $6$ (ring $C$-$C$) + $3$ (ring $C$-$H$) + $2$ ($N$-$H$) + $1$ ($C$-$N$) + $1$ ($O$-$H$) + $1$ ($C$-$O$) + $1$ ($C$-$C$) + $1$ ($C$-$O$) + $1$ ($C$-$O$) + $3$ ($C$-$H$) = $20$. Wait,let's re-count: Ring: $6$ $C$-$C$ $\sigma$,$3$ $C$-$H$ $\sigma$. $-NH_2$: $2$ $N$-$H$ $\sigma$,$1$ $C$-$N$ $\sigma$. $-OH$: $1$ $O$-$H$ $\sigma$,$1$ $C$-$O$ $\sigma$. $-COOCH_3$: $1$ $C$-$C$ $\sigma$,$1$ $C$-$O$ $\sigma$,$1$ $C$-$O$ $\sigma$,$3$ $C$-$H$ $\sigma$. Total $\sigma = 6+3+2+1+1+1+1+1+1+3 = 20$. Correction: The structure is methyl $3-$amino$-5-$hydroxybenzoate. Let's re-verify the structure in the image. It is $3-$amino$-5-$hydroxybenzoate. Total $\sigma$ bonds = $21$,$\pi$ bonds = $4$. Thus,option $B$ is correct.

The total number of $\sigma$ and $\pi$-bonds present in the following compound is:

Similar Questions

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