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(A) The molecular formula $C_5H_{10}$ corresponds to a degree of unsaturation $(DU)$ of $1$. This means the compound can either be cyclic or contain o

Vedclass · Accepted Answer

$7$

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(A) The molecular formula $C_5H_{10}$ corresponds to a degree of unsaturation $(DU)$ of $1$. This means the compound can either be cyclic or contain one double bond.For cyclic isomers,we consider the following structures:$1$. Cyclopentane$2$. Methylcyclobutane$3$. Ethylcyclopropane$4$. $1,1$-Dimethylcyclopropane$5$. cis-$1,2$-Dimethylcyclopropane (optically inactive,meso)$6$. trans-$1,2$-Dimethylcyclopropane (optically active,$d$-isomer)$7$. trans-$1,2$-Dimethylcyclopropane (optically active,$l$-isomer)Counting these,we have $1$ (cyclopentane) + $1$ (methylcyclobutane) + $1$ (ethylcyclopropane) + $1$ ($1,1$-dimethylcyclopropane) + $1$ (cis-$1,2$-dimethylcyclopropane) + $2$ (enantiomers of trans-$1,2$-dimethylcyclopropane) = $7$ isomers.Thus,the total number of cyclic structural and stereoisomers is $7$.

The total number of cyclic structural as well as stereo isomers possible for a compound with the molecular formula $C_5H_{10}$ is

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