The total number of electrons in 18 mL of wa | vedclass

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Question

(B) Given volume of water $= 18 \ mL$ and density $= 1 \ g \ mL^{-1}$.Mass of water $= 	ext{density} 	imes 	ext{volume} = 1 \ g \ mL^{-1} 	imes 18

Vedclass · Accepted Answer

$6.02 	imes 10^{24}$

Vedclass · Answer

(B) Given volume of water $= 18 \ mL$ and density $= 1 \ g \ mL^{-1}$.Mass of water $= 	ext{density} 	imes 	ext{volume} = 1 \ g \ mL^{-1} 	imes 18 \ mL = 18 \ g$.Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \ g \ mol^{-1}$.Number of moles of $H_2O = \frac{18 \ g}{18 \ g \ mol^{-1}} = 1 \ mol$.One molecule of $H_2O$ contains $2 	imes 1 (	ext{from } H) + 8 (	ext{from } O) = 10$ electrons.Total number of electrons in $1 \ mol$ of $H_2O = 1 \ mol 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol} 	imes 10 	ext{ electrons/molecule}$.Total number of electrons $= 6.022 	imes 10^{24}$.

The total number of electrons in $18 \ mL$ of water (density $= 1 \ g \ mL^{-1}$) is

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