The total number of electrons present in 18 | vedclass

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(B) The molar mass of $H_2O$ is $18 \ g/mol$.Given volume $= 18 \ mL$ and density $= 1 \ g/mL$,so the mass of water is $18 \ g$.Number of moles $= \fr

Vedclass · Accepted Answer

$6.023 	imes 10^{24}$

Vedclass · Answer

(B) The molar mass of $H_2O$ is $18 \ g/mol$.Given volume $= 18 \ mL$ and density $= 1 \ g/mL$,so the mass of water is $18 \ g$.Number of moles $= \frac{	ext{mass}}{	ext{molar mass}} = \frac{18 \ g}{18 \ g/mol} = 1 \ mol$.Number of molecules $= 1 \ mol 	imes 6.023 	imes 10^{23} 	ext{ molecules/mol} = 6.023 	imes 10^{23} 	ext{ molecules}$.Each $H_2O$ molecule contains $2$ electrons from $2$ hydrogen atoms and $8$ electrons from $1$ oxygen atom,totaling $10$ electrons per molecule.Total electrons $= 6.023 	imes 10^{23} 	ext{ molecules} 	imes 10 	ext{ electrons/molecule} = 6.023 	imes 10^{24} 	ext{ electrons}$.

The total number of electrons present in $18 \ mL$ water (density $= 1 \ g/mL$) is

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