The total number of monobromo derivatives for | vedclass

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(D) The alkanes with molecular formula $C_{5}H_{12}$ are $n$-pentane,isopentane,and neopentane.$1$. $n$-Pentane $(CH_{3}CH_{2}CH_{2}CH_{2}CH_{3})$ has

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) The alkanes with molecular formula $C_{5}H_{12}$ are $n$-pentane,isopentane,and neopentane.$1$. $n$-Pentane $(CH_{3}CH_{2}CH_{2}CH_{2}CH_{3})$ has $3$ non-equivalent sets of hydrogen atoms,giving $3$ monobromo derivatives.$2$. Isopentane $((CH_{3})_{2}CHCH_{2}CH_{3})$ has $4$ non-equivalent sets of hydrogen atoms,giving $4$ monobromo derivatives.$3$. Neopentane $((CH_{3})_{4}C)$ has $1$ set of equivalent hydrogen atoms,giving $1$ monobromo derivative.Total number of monobromo derivatives = $3 + 4 + 1 = 8$.

The total number of monobromo derivatives formed by the alkanes with molecular formula $C_{5}H_{12}$ is (excluding stereoisomers) $.....$

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