The total number of paramagnetic gaseous prod | vedclass

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(D) Reaction $(A): NH_4 NO_3 \xrightarrow{\Delta} N_2 O + 2 H_2 O$. $N_2 O$ is diamagnetic.Reaction $(B): 2 NaNO_2 + H_2 SO_4 \rightarrow Na_2 SO_4 +

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$3$

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(D) Reaction $(A): NH_4 NO_3 \xrightarrow{\Delta} N_2 O + 2 H_2 O$. $N_2 O$ is diamagnetic.Reaction $(B): 2 NaNO_2 + H_2 SO_4 \rightarrow Na_2 SO_4 + H_2 O + NO_2 + NO$. (Note: The reaction produces $NO$ and $NO_2$, both are paramagnetic).Reaction $(C): 2 Pb(NO_3)_2 \xrightarrow{673 \ K} 2 PbO + 4 NO_2 + O_2$. $NO_2$ and $O_2$ are paramagnetic.The paramagnetic gaseous products are $NO$ (from $B$), $NO_2$ (from $B$ and $C$), and $O_2$ (from $C$).Total number of unique paramagnetic gaseous products is $3$.

The total number of paramagnetic gaseous products formed in all the following reactions $[A + B + C ]$:
$(A)\ NH_4 NO_3 \xrightarrow{\Delta} \text{Products}$
$(B)\ 3 NaNO_2 + 3 H_2 SO_4 \longrightarrow \text{Products}$
$(C)\ Pb(NO_3)_2 \xrightarrow{673 \ K} \text{Products}$

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The total number of paramagnetic gaseous products formed in all the following reactions $[A + B + C ]$:$(A)\ NH_4 NO_3 \xrightarrow{\Delta} \text{Products}$$(B)\ 3 NaNO_2 + 3 H_2 SO_4 \longrightarrow \text{Products}$$(C)\ Pb(NO_3)_2 \xrightarrow{673 \ K} \text{Products}$