The total number of possible isomers for [Pt( | vedclass

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(B) The complex $[Pt(NH_3)_4Cl_2]Br_2$ exhibits ionization isomerism.Possible ionization isomers are:$1$. $[Pt(NH_3)_4Cl_2]Br_2$ (Geometrical isomers:

Vedclass · Accepted Answer

$6$

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(B) The complex $[Pt(NH_3)_4Cl_2]Br_2$ exhibits ionization isomerism.Possible ionization isomers are:$1$. $[Pt(NH_3)_4Cl_2]Br_2$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)$2$. $[Pt(NH_3)_4ClBr]ClBr$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)$3$. $[Pt(NH_3)_4Br_2]Cl_2$ (Geometrical isomers: $cis$ and $trans$,so $2$ isomers)Each ionization isomer has $2$ geometrical isomers.Total isomers = $2 + 2 + 2 = 6$.

List-$I$	List-$II$
$a. [Fe(CN)_{6}]^{3-}$	$i. 5.92 \ BM$
$b. [Fe(H_{2}O)_{6}]^{3+}$	$ii. 0 \ BM$
$c. [Fe(CN)_{6}]^{4-}$	$iii. 4.90 \ BM$
$d. [Fe(H_{2}O)_{6}]^{2+}$	$iv. 1.73 \ BM$

The total number of possible isomers for $[Pt(NH_3)_4Cl_2]Br_2$ is . . . . . . .

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$a. [Fe(CN)_{6}]^{3-}$ $i. 5.92 \ BM$

$b. [Fe(H_{2}O)_{6}]^{3+}$ $ii. 0 \ BM$

$c. [Fe(CN)_{6}]^{4-}$ $iii. 4.90 \ BM$

$d. [Fe(H_{2}O)_{6}]^{2+}$ $iv. 1.73 \ BM$

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