The total number of possible isomers for squa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The square planar complex is of the type $[Mabcd]^{n\pm}$,where $M = Pt^{2+}$,$a = Cl^-$,$b = NO_2^-$,$c = NO_3^-$,and $d = SCN^-$.For a square pl

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) The square planar complex is of the type $[Mabcd]^{n\pm}$,where $M = Pt^{2+}$,$a = Cl^-$,$b = NO_2^-$,$c = NO_3^-$,and $d = SCN^-$.For a square planar complex $[Mabcd]$,there are $3$ geometrical isomers.In this complex,$NO_2^-$ and $SCN^-$ are ambidentate ligands.An ambidentate ligand can coordinate through two different donor atoms.Since there are $2$ ambidentate ligands,each geometrical isomer can exist in $2 	imes 2 = 4$ linkage isomeric forms.Therefore,the total number of isomers = (Number of geometrical isomers) $	imes$ (Number of linkage isomers per geometrical isomer) = $3 	imes 4 = 12$.

The total number of possible isomers for square planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$ is:

Similar Questions

What is the spin-only magnetic moment (in Bohr Magneton units) of $Ni^{2+}$ in an aqueous solution? (Atomic number of $Ni = 28$)

The complexes $[Co(NH_3)_6][Cr(C_2O_4)_3]$ and $[Cr(NH_3)_6][Co(C_2O_4)_3]$ exhibit which type of isomerism?

Arrange the following in the increasing order of the number of unpaired electrons present in the central metal ion:
$I.$ $[MnCl_6]^{3-}$
$II.$ $[FeF_6]^{3-}$
$III.$ $[Mn(CN)_6]^{3-}$
$IV.$ $[Fe(CN)_6]^{3-}$

The magnetic moment of the complex anion $[Cr(NO)(NH_3)(CN)_4]^{2-}$ is $..........$ $B.M.$

Which of the following complex species is not expected to exhibit optical isomerism? $(en = \text{ethylenediamine})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module