The truth table for the given logic circuit i | vedclass

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(B) The given logic circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The output $Y$ is given by the Boolean expression: $Y = \

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(B) The given logic circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate. The output $Y$ is given by the Boolean expression: $Y = \bar{A} \cdot B + A \cdot \bar{B}$. This is the expression for an $XOR$ gate. The truth table is constructed as follows:$A$$B$$Y$$0$$0$$0$$0$$1$$1$$1$$0$$1$$1$$1$$0$Comparing this with the given options, Option $B$ represents the correct truth table.

The truth table for the given logic circuit is

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