The truth table given below is for which gate | vedclass

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(D) For a $NAND$ gate,the output $C$ is given by the Boolean expression $C = \overline{A \cdot B}$.Checking the values:$1$. For $A = 0, B = 0$: $C = \

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$NAND$

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(D) For a $NAND$ gate,the output $C$ is given by the Boolean expression $C = \overline{A \cdot B}$.Checking the values:$1$. For $A = 0, B = 0$: $C = \overline{0 \cdot 0} = \overline{0} = 1$.$2$. For $A = 0, B = 1$: $C = \overline{0 \cdot 1} = \overline{0} = 1$.$3$. For $A = 1, B = 0$: $C = \overline{1 \cdot 0} = \overline{0} = 1$.$4$. For $A = 1, B = 1$: $C = \overline{1 \cdot 1} = \overline{1} = 0$.Comparing these results with the given table,the output matches the $NAND$ gate logic.

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

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The truth table given below is for which gate?$A: 0, 0, 1, 1$$B: 0, 1, 0, 1$$C: 1, 1, 1, 0$