The two ends of a uniform conductor are joine | vedclass

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(B) When we move in the direction of the current in a uniform conductor,the potential $V$ decreases linearly due to the potential drop across the resi

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(B) When we move in the direction of the current in a uniform conductor,the potential $V$ decreases linearly due to the potential drop across the resistance of the conductor $(V = IR)$.When we pass through the cell from its negative terminal to its positive terminal,the potential increases by an amount equal to the terminal potential difference of the cell,which is given by $V = E - Ir$.Since the cell is driving current,the terminal potential difference $V$ is less than the $e.m.f.$ $E$ of the cell.Therefore,the graph should show a linear decrease in potential along the conductor,followed by a sharp increase across the cell that is less than $E$,and finally another linear decrease as we complete the path back to the midpoint $P$.

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