The types of hybridisation on the five carbon | vedclass

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(A) The structure of $pent-1-en-4-yne$ is $CH_2=CH-CH_2-C \equiv CH$.Let us determine the hybridisation of each carbon atom:$C_1$: $CH_2=$ (double bon

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$sp^2, sp^2, sp^3, sp, sp$

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(A) The structure of $pent-1-en-4-yne$ is $CH_2=CH-CH_2-C \equiv CH$.Let us determine the hybridisation of each carbon atom:$C_1$: $CH_2=$ (double bond),so it is $sp^2$ hybridised.$C_2$: $-CH=$ (double bond),so it is $sp^2$ hybridised.$C_3$: $-CH_2-$ (all single bonds),so it is $sp^3$ hybridised.$C_4$: $-C \equiv$ (triple bond),so it is $sp$ hybridised.$C_5$: $\equiv CH$ (triple bond),so it is $sp$ hybridised.Thus,the hybridisation sequence from left to right is $sp^2, sp^2, sp^3, sp, sp$.

The types of hybridisation on the five carbon atoms from left to right in $pent-1-en-4-yne$ are

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