The typical transfer characteristic of a tran | vedclass

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(B) The current gain $\beta$ in $CE$ configuration is given by $\beta = \frac{\Delta I_C}{\Delta I_B}$.From the graph,we can choose two points to calc

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$200$

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(B) The current gain $\beta$ in $CE$ configuration is given by $\beta = \frac{\Delta I_C}{\Delta I_B}$.From the graph,we can choose two points to calculate the change in collector current $\Delta I_C$ and base current $\Delta I_B$.Let us take the points $(I_B = 100\,\mu A, I_C = 5\,mA)$ and $(I_B = 200\,\mu A, I_C = 10\,mA)$.$\Delta I_C = (10 - 5)\,mA = 5\,mA = 5 	imes 10^{-3}\,A$.$\Delta I_B = (200 - 100)\,\mu A = 100\,\mu A = 100 	imes 10^{-6}\,A$.Therefore,$\beta = \frac{5 	imes 10^{-3}}{100 	imes 10^{-6}} = \frac{5000}{100} = 50$.The voltage gain $A_V$ is given by $A_V = \beta 	imes \frac{R_C}{R_{in}}$.Given $R_C = 2\,k\Omega$ and $R_{in} = 0.50\,k\Omega$.$A_V = 50 	imes \frac{2\,k\Omega}{0.50\,k\Omega} = 50 	imes 4 = 200$.

The typical transfer characteristic of a transistor in $CE$ configuration is shown in the figure. $A$ load resistor of $2\,k\Omega$ is connected in the collector branch of the circuit used. The input resistance of the transistor is $0.50\,k\Omega$. The voltage gain of the transistor is:

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