The uncertainty of velocity of an electron is | vedclass

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(A) According to Heisenberg's uncertainty principle,$\Delta x \cdot \Delta v \geq \frac{h}{4 \pi m}$.Given: $\Delta v = 5.7 	imes 10^5 \ m \ s^{-1}$,

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$1.0 	imes 10^{-10} \ m$

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(A) According to Heisenberg's uncertainty principle,$\Delta x \cdot \Delta v \geq \frac{h}{4 \pi m}$.Given: $\Delta v = 5.7 	imes 10^5 \ m \ s^{-1}$,$h = 6.626 	imes 10^{-34} \ kg \ m^2 \ s^{-1}$,$m = 9.11 	imes 10^{-31} \ kg$.Substituting the values:$\Delta x = \frac{h}{4 \pi m \Delta v} = \frac{6.626 	imes 10^{-34}}{4 	imes 3.14 	imes 9.11 	imes 10^{-31} 	imes 5.7 	imes 10^5}$.$\Delta x \approx 1.01 	imes 10^{-10} \ m$.

The uncertainty of velocity of an electron is $5.7 \times 10^5 \ m \ s^{-1}$. Find its uncertainty in position.

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