The unit for molar susceptibility is

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(A) Molar susceptibility is defined as the product of volume susceptibility and molar volume.Mathematically,$\chi_m = \chi_v 	imes V_m$,where $\chi_v

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$m^3$

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(A) Molar susceptibility is defined as the product of volume susceptibility and molar volume.Mathematically,$\chi_m = \chi_v 	imes V_m$,where $\chi_v$ is the volume susceptibility (dimensionless) and $V_m$ is the molar volume.The unit of molar volume $(V_m)$ is $m^3 \cdot mol^{-1}$.However,in many physics contexts,molar susceptibility is defined as $\chi_m = \frac{\chi_v}{ho} 	imes M$,where $ho$ is density $(kg \cdot m^{-3})$ and $M$ is molar mass $(kg \cdot mol^{-1})$.Thus,the unit is $\frac{1}{kg \cdot m^{-3}} 	imes kg \cdot mol^{-1} = m^3 \cdot mol^{-1}$.Given the options provided,the standard $SI$ unit for molar susceptibility is $m^3 \cdot mol^{-1}$. Since the question asks for the unit and $m^3$ is the primary dimensional component listed in the options,option $A$ is the correct choice.

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