The unit of rate constant for a zero order re | vedclass

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Question

(A) The rate law expression for a zero order reaction is given by: $	ext{Rate} = k[A]^0$.Since the rate of reaction is expressed in units of concentr

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$mol\, L^{-1}\, s^{-1}$

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(A) The rate law expression for a zero order reaction is given by: $	ext{Rate} = k[A]^0$.Since the rate of reaction is expressed in units of concentration per unit time $(mol\, L^{-1}\, s^{-1})$,we have:$mol\, L^{-1}\, s^{-1} = k 	imes (mol\, L^{-1})^0$.Since any value raised to the power of $0$ is $1$,the unit of $k$ is equal to the unit of the rate of reaction.Therefore,the unit of the rate constant for a zero order reaction is $mol\, L^{-1}\, s^{-1}$.

$[R] \ (M)$	$1.0$	$0.76$	$0.40$	$0.10$
$t \ (min)$	$0.0$	$0.05$	$0.12$	$0.18$

The unit of rate constant for a zero order reaction is

Similar Questions

Which of the following reactions end in finite time?

Mention True $(T)$ and False $(F)$ statements for the following regarding a zero-order reaction $R \rightarrow P$:
$1. \ t_{1/2} \propto [R]_0$
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For the reaction $R \rightarrow P$,the concentration of $R$ is measured as a function of time and the following data is obtained:

$[R] \ (M)$ $1.0$ $0.76$ $0.40$ $0.10$

$t \ (min)$ $0.0$ $0.05$ $0.12$ $0.18$

The order of the reaction is:

The reaction $2A \rightarrow B + C$ follows zero-order kinetics when:

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